How It Works

Hydraulic System Efficiency

Overall system efficiency is the ratio of useful output power to input power. In hydraulic systems, energy is lost at each component as fluid power is converted to mechanical work.

Overall Efficiency = Output Power / Input Power x 100%

Or expressed as component efficiencies multiplied together:

System Eff = Pump Eff x Valve Eff x Line Eff x Actuator Eff

Component Efficiency Breakdown

Pump Efficiency (80-95%): Combines volumetric efficiency (internal leakage) and mechanical efficiency (friction losses). Variable displacement pumps at partial stroke have lower volumetric efficiency.

Valve Losses (85-98%): Pressure drops across directional valves, proportional valves, and flow controls convert hydraulic energy to heat. Proportional and servo systems with throttling control can have significant valve losses.

Line Losses (90-98%): Friction in hoses, tubes, and fittings causes pressure drop. Undersized lines dramatically increase losses. Line loss varies with flow rate squared.

Actuator Efficiency (90-98%): Cylinders lose efficiency to seal friction and internal leakage. Hydraulic motors have both volumetric and mechanical losses similar to pumps.

Power Calculations

Hydraulic power can be calculated from pressure and flow:

Power (HP) = Pressure (PSI) x Flow (GPM) / 1714

Power (kW) = Pressure (bar) x Flow (L/min) / 600

Mechanical output power from a cylinder:

Power (HP) = Force (lbs) x Velocity (ft/min) / 33,000

Typical System Efficiencies

System TypeTypical EfficiencyNotes
Load-sensing system65-80%Variable pump matches load
Constant pressure system50-70%Relief valve bypass losses
Throttle-controlled30-50%Significant valve losses
Hydrostatic transmission75-85%Closed loop, high efficiency
Servo/proportional40-60%Control accuracy vs efficiency

Sankey Diagram Concept

A Sankey diagram visualizes energy flow through a system. The width of each flow represents the amount of power. Branches show where power is lost as heat at each component, with the remaining flow representing useful output.

Hydraulic System Power Flow (Sankey Concept) INPUT 100 HP Electric Motor PUMP 87% eff -13 HP loss VALVES 92% eff -7 HP loss LINES 95% eff -4 HP loss ACTUATOR 95% eff -4 HP loss OUTPUT: 72 HP 72% Overall Efficiency 72% = 87% x 92% x 95% x 95% HEAT

System Efficiency Calculator

Calculate overall hydraulic system efficiency and visualize power flow from input to useful output work.

Power Inputs

Or calculate output from force and velocity:

Calculating...
Overall efficiency = --

Efficiency Results

Overall System Efficiency --
Useful Output Power --
Input Power --
Total Power Lost (Heat) --
Heat Generated --
Power Flow Breakdown
64%
15%
10%
5%
6%
Useful: --
Pump: --
Valve: --
Line: --
Actuator: --
Component-by-Component
Pump 85% -7.5 HP
Valves 90% -4.3 HP
Lines 95% -1.9 HP
Actuator 95% -1.8 HP

Power Flow Diagram

Typical Component Efficiencies

ComponentEfficiency RangeFactors
Piston Pump87 - 95%Displacement, pressure
Vane Pump82 - 92%Wear, pressure
Gear Pump80 - 90%Clearances, pressure
Directional Valve95 - 98%Size, flow rate
Proportional Valve85 - 95%Control method
Flow Control (throttle)50 - 80%Pressure drop
Well-Sized Lines95 - 98%Velocity, length
Cylinder95 - 98%Seals, rod size
Hydraulic Motor85 - 95%Type, displacement