How It Works

Heat Generation in Hydraulic Systems

Every hydraulic system generates heat due to inefficiencies. The total heat load must be dissipated to maintain fluid temperature within acceptable limits (typically 40-60C / 104-140F).

Heat Sources

  • Pump losses: Mechanical and volumetric inefficiency (typically 10-20% of input power)
  • Relief valve flow: Full power converted to heat when oil bypasses
  • Pressure drops: Valves, fittings, lines all generate heat
  • Motor inefficiency: Mechanical losses in hydraulic motors
  • Cylinder friction: Seal and rod friction losses

Heat Load Calculation

Total heat = Input Power - Useful Work Output

Q_heat = P_input x (1 - Overall Efficiency)

Or for specific components:

Q = P x dP / 600 (kW, where P is LPM and dP is bar)

Thermal Balance

At equilibrium: Heat Generated = Heat Dissipated

Heat dissipation occurs through:

  • Reservoir surface (natural convection)
  • Lines and components (conduction/convection)
  • Oil cooler (forced convection)

Heat Load Calculator

Calculate total system heat load from multiple sources and determine cooling requirements.

Pump Parameters
Relief Valve Losses
Valve & Line Losses
Motor/Actuator Efficiency
Reservoir & Ambient
Ready to Calculate
Enter system parameters

Heat Load Analysis

Total Heat Load --
Pump Inefficiency Heat --
Relief Valve Heat --
Valve/Line Heat --
Average Heat (with duty) --
System Efficiency --
Thermal Capacity
Cool Warm Hot
Reservoir Natural Dissipation --
Required Cooler Capacity --
Est. Temp Rise (no cooler) --

Typical Heat Values

SourceHeat as % of Input
Pump (85% eff)15%
Relief valve (bypass)100% of bypass power
Directional valves3-5%
Flow controls5-15%
Lines & fittings1-3%